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What is the voltage a 35.0 (omega symbol) resistor with a current of 4 1/2 amp?

Author : ej

Submitted : 2018-06-14 04:46:49    Popularity:     

Tags: omega  35.0  voltage  symbol  amp  

voltage drop = 35 ohm*4.5 Amps = 140+17.5 = 157.5 Volt Please always phrase the question thus: What is the voltage across a 35 Ω resistor when a cur

Answers:

voltage drop = 35 ohm*4.5 Amps = 140+17.5 = 157.5 Volt

Please always phrase the question thus: What is the voltage across a 35 Ω resistor when a current of 4.5 A passes through it?
Formula E = I * R where I = 4.5 A and R = 35 Ω.
So, E = 157.5 v as most answers above show.

E = (IR) = (4.5 x 35) = 157.5 VOLTS.

Apply smithy's law.
"A student that does not learn their formulae and cannot do their homework will quickly fail"

So you "know" that V = IR
= 4.5 * 35 = 157.5 Volts

So where is the problem?

Learn your formulas

https://www.google.com/imgres?imgurl=htt...

V = I * R

35.0 volts

"ohms" is the term.

E = IR = 35 x 4.5 = 157.5 volts

Use the following equation.

V = I * R = 4.5 * 35 = 157.5 amps



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