Is this a conditional probability question P(BA)=P(A), or is it asking for the probability of the Y
Submitted : 20180614 08:02:09 Popularity:
Tags: question probability conditional scoring winning
This season the probability that the Yankees will win a game is 1/3 and the probability that the Yankees will score 5 or more runs in a game is 3/8. The probability that the Yankees win or score more than 5 runs is 4/7. What is the probability that the Ya
What events are A and B?
P(w) = 1/3
P(5+) = 3/8
P(w) U P(5+) = 4/7
1/3 + 3/8 = 17/24 which is not 4/7, so there is an intersection.
1/3 +3/8 4/7 = 23/168 which is P(both)
(23/168)/(3/8) = 23/63
This is a conditional probability question.
A = Yankees will win
B = Yankees will score 5 or more runs
GivenL
P(A) = 1/3
P(B) = 3/8
P(A or B) = 4/7
P(A and B)
= P(A) + P(B)  P(A or B)
= (1/3) + (3/8)  (4/7)
= (56/168) + (63/168)  (96/168)
= 23/168
Probability that the Yankees will win when they score more than 5 runs
= P(AB)
= P(A and B) / P(B)
= (23/168) / (3/8)
= (23/168) × (8/3)
= 23/63
= 0.4 (to the nearest tenth)
It's conditional probability. It's asking for the probability the Yankees win *when* (or *given*) they score more than 5 runs.
Let A be the event the Yankees win.
Let B be the event the Yankees score more than 5 runs.
You have:
P(A) = 1/3
P(B) = 3/8
P(A or B) = 4/7
Use this rule:
P(A or B) = P(A) + P(B)  P(A and B)
From that you can calculate:
P(A and B)
Then use this rule:
P(AB) = P(A and B) / P(B)
I could calculate it out for you, but I've given you all the steps and I think you can take it from here.
It's conditional probability. What is the probability that they win, GIVEN that they score more than 5 runs.
That would be P(score more than 5 AND win) divided by P(score more than 5).
No


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